Base | Representation |
---|---|
bin | 10011101011101001110… |
… | …010011011111110010111 |
3 | 11210022010222110211201211 |
4 | 103223221302123332113 |
5 | 134130001230402210 |
6 | 2513203234002251 |
7 | 166501152453316 |
oct | 23535162337627 |
9 | 4708128424654 |
10 | 1352542044055 |
11 | 4816787a55a4 |
12 | 19a16b716387 |
13 | 9a70c6c7637 |
14 | 4966b75227d |
15 | 252b1a4d38a |
hex | 13ae9c9bf97 |
1352542044055 has 8 divisors (see below), whose sum is σ = 1627472935872. Its totient is φ = 1079085313248.
The previous prime is 1352542044043. The next prime is 1352542044103. The reversal of 1352542044055 is 5504402452531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1352542044055 - 27 = 1352542043927 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1352542043999 and 1352542044017.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 368538232 + ... + 368541901.
It is an arithmetic number, because the mean of its divisors is an integer number (203434116984).
Almost surely, 21352542044055 is an apocalyptic number.
1352542044055 is a deficient number, since it is larger than the sum of its proper divisors (274930891817).
1352542044055 is an equidigital number, since it uses as much as digits as its factorization.
1352542044055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 737080505.
The product of its (nonzero) digits is 480000, while the sum is 40.
Adding to 1352542044055 its reverse (5504402452531), we get a palindrome (6856944496586).
The spelling of 1352542044055 in words is "one trillion, three hundred fifty-two billion, five hundred forty-two million, forty-four thousand, fifty-five".
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