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13530354373 is a prime number
BaseRepresentation
bin11001001100111100…
…01101001011000101
31021220221202012220001
430212132031023011
5210202232314443
610114334241301
7656203054204
oct144636151305
937827665801
1013530354373
115813594558
122757356231
131378224163
14924d8323b
15542cb3d4d
hex32678d2c5

13530354373 has 2 divisors, whose sum is σ = 13530354374. Its totient is φ = 13530354372.

The previous prime is 13530354293. The next prime is 13530354391. The reversal of 13530354373 is 37345303531.

13530354373 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12422662849 + 1107691524 = 111457^2 + 33282^2 .

It is an emirp because it is prime and its reverse (37345303531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13530354373 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13530354073) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765177186 + 6765177187.

It is an arithmetic number, because the mean of its divisors is an integer number (6765177187).

Almost surely, 213530354373 is an apocalyptic number.

It is an amenable number.

13530354373 is a deficient number, since it is larger than the sum of its proper divisors (1).

13530354373 is an equidigital number, since it uses as much as digits as its factorization.

13530354373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 170100, while the sum is 37.

The spelling of 13530354373 in words is "thirteen billion, five hundred thirty million, three hundred fifty-four thousand, three hundred seventy-three".