13531113433 has 8 divisors (see below), whose sum is σ = 14329473480. Its totient is φ = 12733021440.

The previous prime is 13531113419. The next prime is 13531113469. The reversal of 13531113433 is 33431113531.

13531113433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 1270423449 + 12260689984 = 35643^2 + 110728^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13531113433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13531113403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42003 + ... + 169783.

It is an arithmetic number, because the mean of its divisors is an integer number (1791184185).

Almost surely, 2^13531113433 is an apocalyptic number.

It is an amenable number.

13531113433 is a deficient number, since it is larger than the sum of its proper divisors (798360047).

13531113433 is a wasteful number, since it uses less digits than its factorization.

13531113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 134027.

The product of its digits is 4860, while the sum is 28.

Adding to 13531113433 its reverse (33431113531), we get a palindrome (46962226964).

The spelling of 13531113433 in words is "thirteen billion, five hundred thirty-one million, one hundred thirteen thousand, four hundred thirty-three".