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13531212035 = 511793114203
BaseRepresentation
bin11001001101000010…
…11110100100000011
31021221000100210101022
430212201132210003
5210202442241120
610114404500055
7656213255525
oct144641364403
937830323338
1013531212035
11581401a970
1227576aa62b
131378464653
14925127a15
15542dd3025
hex32685e903

13531212035 has 16 divisors (see below), whose sum is σ = 17937815040. Its totient is φ = 9716310240.

The previous prime is 13531211971. The next prime is 13531212047. The reversal of 13531212035 is 53021213531.

It is not a de Polignac number, because 13531212035 - 26 = 13531211971 is a prime.

It is a super-2 number, since 2×135312120352 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13531211995 and 13531212013.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1552757 + ... + 1561446.

It is an arithmetic number, because the mean of its divisors is an integer number (1121113440).

Almost surely, 213531212035 is an apocalyptic number.

13531212035 is a deficient number, since it is larger than the sum of its proper divisors (4406603005).

13531212035 is a wasteful number, since it uses less digits than its factorization.

13531212035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3114298.

The product of its (nonzero) digits is 2700, while the sum is 26.

Adding to 13531212035 its reverse (53021213531), we get a palindrome (66552425566).

The spelling of 13531212035 in words is "thirteen billion, five hundred thirty-one million, two hundred twelve thousand, thirty-five".

Divisors: 1 5 11 55 79 395 869 4345 3114203 15571015 34256233 171281165 246022037 1230110185 2706242407 13531212035