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135312301 = 606722303
BaseRepresentation
bin10000001000010…
…11001110101101
3100102121120120201
420010023032231
5234114443201
621232113501
73232064335
oct1004131655
9312546521
10135312301
116a420153
1239395891
1322058767
1413d840c5
15bd2c801
hex810b3ad

135312301 has 4 divisors (see below), whose sum is σ = 135340672. Its totient is φ = 135283932.

The previous prime is 135312211. The next prime is 135312323. The reversal of 135312301 is 103213531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135312301 - 213 = 135304109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135312361) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5085 + ... + 17218.

It is an arithmetic number, because the mean of its divisors is an integer number (33835168).

Almost surely, 2135312301 is an apocalyptic number.

It is an amenable number.

135312301 is a deficient number, since it is larger than the sum of its proper divisors (28371).

135312301 is an equidigital number, since it uses as much as digits as its factorization.

135312301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28370.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 135312301 is about 11632.3815704266. The cubic root of 135312301 is about 513.3880550629.

Adding to 135312301 its reverse (103213531), we get a palindrome (238525832).

The spelling of 135312301 in words is "one hundred thirty-five million, three hundred twelve thousand, three hundred one".

Divisors: 1 6067 22303 135312301