Base | Representation |
---|---|
bin | 11110110001000011101111… |
… | …001010100010011001011111 |
3 | 122202002202122002020100211011 |
4 | 132301003233022202121133 |
5 | 120213430313011211033 |
6 | 1155441440122440051 |
7 | 40334005624332655 |
oct | 3661035712423137 |
9 | 582082562210734 |
10 | 135312662210143 |
11 | 3a129861250970 |
12 | 13214600963027 |
13 | 5a66c1087a392 |
14 | 255b24c602dd5 |
15 | 1099bd5e04ccd |
hex | 7b10ef2a265f |
135312662210143 has 8 divisors (see below), whose sum is σ = 147613955783040. Its totient is φ = 123011392381080.
The previous prime is 135312662210111. The next prime is 135312662210149. The reversal of 135312662210143 is 341012266213531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 135312662210143 - 25 = 135312662210111 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135312662210096 and 135312662210105.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135312662210149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7254168 + ... + 17979106.
It is an arithmetic number, because the mean of its divisors is an integer number (18451744472880).
Almost surely, 2135312662210143 is an apocalyptic number.
135312662210143 is a deficient number, since it is larger than the sum of its proper divisors (12301293572897).
135312662210143 is a wasteful number, since it uses less digits than its factorization.
135312662210143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11871917.
The product of its (nonzero) digits is 155520, while the sum is 40.
The spelling of 135312662210143 in words is "one hundred thirty-five trillion, three hundred twelve billion, six hundred sixty-two million, two hundred ten thousand, one hundred forty-three".
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