Base | Representation |
---|---|
bin | 11001001101000101… |
… | …00101011111001101 |
3 | 1021221000220112212210 |
4 | 30212202211133031 |
5 | 210203031040131 |
6 | 10114415021033 |
7 | 656215605504 |
oct | 144642453715 |
9 | 37830815783 |
10 | 13531502541 |
11 | 58141a9157 |
12 | 275780a779 |
13 | 137853694b |
14 | 9251a183b |
15 | 542e3e146 |
hex | 3268a57cd |
13531502541 has 4 divisors (see below), whose sum is σ = 18042003392. Its totient is φ = 9021001692.
The previous prime is 13531502513. The next prime is 13531502561. The reversal of 13531502541 is 14520513531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 13531502541 - 218 = 13531240397 is a prime.
It is a super-2 number, since 2×135315025412 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13531502499 and 13531502508.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13531502561) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2255250421 + ... + 2255250426.
It is an arithmetic number, because the mean of its divisors is an integer number (4510500848).
Almost surely, 213531502541 is an apocalyptic number.
It is an amenable number.
13531502541 is a deficient number, since it is larger than the sum of its proper divisors (4510500851).
13531502541 is an equidigital number, since it uses as much as digits as its factorization.
13531502541 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4510500850.
The product of its (nonzero) digits is 9000, while the sum is 30.
The spelling of 13531502541 in words is "thirteen billion, five hundred thirty-one million, five hundred two thousand, five hundred forty-one".
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