Base | Representation |
---|---|
bin | 11001001101001001… |
… | …00011110100101101 |
3 | 1021221001212211201102 |
4 | 30212210203310231 |
5 | 210203144120023 |
6 | 10114434052445 |
7 | 656223162251 |
oct | 144644436455 |
9 | 37831784642 |
10 | 13532020013 |
11 | 5814521a16 |
12 | 2757a1a125 |
13 | 1378688345 |
14 | 925298261 |
15 | 542ee2628 |
hex | 326923d2d |
13532020013 has 2 divisors, whose sum is σ = 13532020014. Its totient is φ = 13532020012.
The previous prime is 13532019971. The next prime is 13532020067. The reversal of 13532020013 is 31002023531.
13532020013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8994246244 + 4537773769 = 94838^2 + 67363^2 .
It is a cyclic number.
It is not a de Polignac number, because 13532020013 - 220 = 13530971437 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13532020613) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6766010006 + 6766010007.
It is an arithmetic number, because the mean of its divisors is an integer number (6766010007).
Almost surely, 213532020013 is an apocalyptic number.
It is an amenable number.
13532020013 is a deficient number, since it is larger than the sum of its proper divisors (1).
13532020013 is an equidigital number, since it uses as much as digits as its factorization.
13532020013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 540, while the sum is 20.
Adding to 13532020013 its reverse (31002023531), we get a palindrome (44534043544).
The spelling of 13532020013 in words is "thirteen billion, five hundred thirty-two million, twenty thousand, thirteen".
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