Base | Representation |
---|---|
bin | 111111000000110110… |
… | …1101001111111101111 |
3 | 110221021200212012022122 |
4 | 1332001231221333233 |
5 | 4204113433344120 |
6 | 142055405503155 |
7 | 12530234565551 |
oct | 1760155517757 |
9 | 427250765278 |
10 | 135320215535 |
11 | 5243080887a |
12 | 22286571abb |
13 | c9b718b76b |
14 | 6799cc34d1 |
15 | 37bee6da25 |
hex | 1f81b69fef |
135320215535 has 4 divisors (see below), whose sum is σ = 162384258648. Its totient is φ = 108256172424.
The previous prime is 135320215531. The next prime is 135320215673. The reversal of 135320215535 is 535512023531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135320215535 - 22 = 135320215531 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135320215495 and 135320215504.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135320215531) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13532021549 + ... + 13532021558.
It is an arithmetic number, because the mean of its divisors is an integer number (40596064662).
Almost surely, 2135320215535 is an apocalyptic number.
135320215535 is a deficient number, since it is larger than the sum of its proper divisors (27064043113).
135320215535 is an equidigital number, since it uses as much as digits as its factorization.
135320215535 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27064043112.
The product of its (nonzero) digits is 67500, while the sum is 35.
The spelling of 135320215535 in words is "one hundred thirty-five billion, three hundred twenty million, two hundred fifteen thousand, five hundred thirty-five".
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