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1353316398720 = 2735111319594397
BaseRepresentation
bin10011101100010111111…
…100010111011010000000
311210101010221120010122020
4103230113330113122000
5134133042444224340
62513412135041440
7166526304406146
oct23542774273200
94711127503566
101353316398720
11481a3590a730
1219a346b10280
139a803c6b670
1449702523596
1525309a0b9d0
hex13b17f17680

1353316398720 has 1024 divisors, whose sum is σ = 5426217216000. Its totient is φ = 281974210560.

The previous prime is 1353316398689. The next prime is 1353316398743. The reversal of 1353316398720 is 278936133531.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 307779562 + ... + 307783958.

It is an arithmetic number, because the mean of its divisors is an integer number (5299040250).

Almost surely, 21353316398720 is an apocalyptic number.

1353316398720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1353316398720, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2713108608000).

1353316398720 is an abundant number, since it is smaller than the sum of its proper divisors (4072900817280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1353316398720 is a wasteful number, since it uses less digits than its factorization.

1353316398720 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4521 (or 4509 counting only the distinct ones).

The product of its (nonzero) digits is 2449440, while the sum is 51.

The spelling of 1353316398720 in words is "one trillion, three hundred fifty-three billion, three hundred sixteen million, three hundred ninety-eight thousand, seven hundred twenty".