Base | Representation |
---|---|
bin | 111111000001010010… |
… | …1000101000011100111 |
3 | 110221022201012100000212 |
4 | 1332002211011003213 |
5 | 4204131143304140 |
6 | 142101045130035 |
7 | 12530502226502 |
oct | 1760245050347 |
9 | 427281170025 |
10 | 135334744295 |
11 | 52438a31513 |
12 | 2228b3b991b |
13 | c9ba1a776a |
14 | 679bbc6139 |
15 | 37c138d765 |
hex | 1f829450e7 |
135334744295 has 4 divisors (see below), whose sum is σ = 162401693160. Its totient is φ = 108267795432.
The previous prime is 135334744283. The next prime is 135334744297. The reversal of 135334744295 is 592447433531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 592447433531 = 1231 ⋅481273301.
It is a cyclic number.
It is not a de Polignac number, because 135334744295 - 26 = 135334744231 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135334744297) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13533474425 + ... + 13533474434.
It is an arithmetic number, because the mean of its divisors is an integer number (40600423290).
Almost surely, 2135334744295 is an apocalyptic number.
135334744295 is a deficient number, since it is larger than the sum of its proper divisors (27066948865).
135334744295 is an equidigital number, since it uses as much as digits as its factorization.
135334744295 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27066948864.
The product of its digits is 5443200, while the sum is 50.
The spelling of 135334744295 in words is "one hundred thirty-five billion, three hundred thirty-four million, seven hundred forty-four thousand, two hundred ninety-five".
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