Base | Representation |
---|---|
bin | 11110110001011001001111… |
… | …001101100100110000101110 |
3 | 122202011222020000002010202101 |
4 | 132301121033031210300232 |
5 | 120214320103101033340 |
6 | 1155500215021045314 |
7 | 40335454003226443 |
oct | 3661311715446056 |
9 | 582158200063671 |
10 | 135335748455470 |
11 | 3a138628897762 |
12 | 13218b843b683a |
13 | 5a6914c775484 |
14 | 255c3dc7419ca |
15 | 109a5d7a9dc9a |
hex | 7b164f364c2e |
135335748455470 has 64 divisors (see below), whose sum is σ = 246146822553600. Its totient is φ = 53571643453440.
The previous prime is 135335748455447. The next prime is 135335748455471. The reversal of 135335748455470 is 74554847533531.
It is a happy number.
It is a super-3 number, since 3×1353357484554703 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135335748455471) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 806402926 + ... + 806570734.
It is an arithmetic number, because the mean of its divisors is an integer number (3846044102400).
Almost surely, 2135335748455470 is an apocalyptic number.
135335748455470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
135335748455470 is a deficient number, since it is larger than the sum of its proper divisors (110811074098130).
135335748455470 is a wasteful number, since it uses less digits than its factorization.
135335748455470 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 169553.
The product of its (nonzero) digits is 423360000, while the sum is 64.
The spelling of 135335748455470 in words is "one hundred thirty-five trillion, three hundred thirty-five billion, seven hundred forty-eight million, four hundred fifty-five thousand, four hundred seventy".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •