Base | Representation |
---|---|
bin | 10011101100011010111… |
… | …011111101011110000011 |
3 | 11210101021110001211221122 |
4 | 103230122323331132003 |
5 | 134133143323433011 |
6 | 2513421131342455 |
7 | 166530454333004 |
oct | 23543273753603 |
9 | 4711243054848 |
10 | 1353366624131 |
11 | 481a611a4835 |
12 | 19a35b8b1a2b |
13 | 9a8114a5542 |
14 | 497090791ab |
15 | 2530e12d3db |
hex | 13b1aefd783 |
1353366624131 has 2 divisors, whose sum is σ = 1353366624132. Its totient is φ = 1353366624130.
The previous prime is 1353366624121. The next prime is 1353366624133. The reversal of 1353366624131 is 1314266633531.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1353366624131 - 218 = 1353366361987 is a prime.
It is a super-2 number, since 2×13533666241312 (a number of 25 digits) contains 22 as substring.
Together with 1353366624133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1353366624133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676683312065 + 676683312066.
It is an arithmetic number, because the mean of its divisors is an integer number (676683312066).
Almost surely, 21353366624131 is an apocalyptic number.
1353366624131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353366624131 is an equidigital number, since it uses as much as digits as its factorization.
1353366624131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 699840, while the sum is 44.
The spelling of 1353366624131 in words is "one trillion, three hundred fifty-three billion, three hundred sixty-six million, six hundred twenty-four thousand, one hundred thirty-one".
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