Base | Representation |
---|---|
bin | 11001001101011000… |
… | …10100001101010111 |
3 | 1021221012201010201220 |
4 | 30212230110031113 |
5 | 210204204200312 |
6 | 10114545421423 |
7 | 656246361033 |
oct | 144654241527 |
9 | 37835633656 |
10 | 13534053207 |
11 | 5815690544 |
12 | 275863a873 |
13 | 1378c1a90c |
14 | 9256671c3 |
15 | 543294c8c |
hex | 326b14357 |
13534053207 has 4 divisors (see below), whose sum is σ = 18045404280. Its totient is φ = 9022702136.
The previous prime is 13534053193. The next prime is 13534053223. The reversal of 13534053207 is 70235043531.
13534053207 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13534053207 - 228 = 13265617751 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13534053287) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2255675532 + ... + 2255675537.
It is an arithmetic number, because the mean of its divisors is an integer number (4511351070).
Almost surely, 213534053207 is an apocalyptic number.
13534053207 is a deficient number, since it is larger than the sum of its proper divisors (4511351073).
13534053207 is an equidigital number, since it uses as much as digits as its factorization.
13534053207 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4511351072.
The product of its (nonzero) digits is 37800, while the sum is 33.
Adding to 13534053207 its reverse (70235043531), we get a palindrome (83769096738).
The spelling of 13534053207 in words is "thirteen billion, five hundred thirty-four million, fifty-three thousand, two hundred seven".
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