Base | Representation |
---|---|
bin | 10011101100011110001… |
… | …000001010101110000001 |
3 | 11210101102011210112120012 |
4 | 103230132020022232001 |
5 | 134133301024441102 |
6 | 2513430322554305 |
7 | 166532004336644 |
oct | 23543610125601 |
9 | 4711364715505 |
10 | 1353420155777 |
11 | 481a89437968 |
12 | 19a375808995 |
13 | 9a81c5c9281 |
14 | 49712211a5b |
15 | 25313ba4752 |
hex | 13b1e20ab81 |
1353420155777 has 4 divisors (see below), whose sum is σ = 1412264510400. Its totient is φ = 1294575801156.
The previous prime is 1353420155761. The next prime is 1353420155837. The reversal of 1353420155777 is 7775510243531.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1353420155777 - 24 = 1353420155761 is a prime.
It is a super-2 number, since 2×13534201557772 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1353420155177) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29422177277 + ... + 29422177322.
It is an arithmetic number, because the mean of its divisors is an integer number (353066127600).
Almost surely, 21353420155777 is an apocalyptic number.
It is an amenable number.
1353420155777 is a deficient number, since it is larger than the sum of its proper divisors (58844354623).
1353420155777 is an equidigital number, since it uses as much as digits as its factorization.
1353420155777 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58844354622.
The product of its (nonzero) digits is 3087000, while the sum is 50.
The spelling of 1353420155777 in words is "one trillion, three hundred fifty-three billion, four hundred twenty million, one hundred fifty-five thousand, seven hundred seventy-seven".
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