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13534205003 = 111230382273
BaseRepresentation
bin11001001101011001…
…11001010001001011
31021221012222211221222
430212230321101023
5210204224030003
610114552552255
7656250562424
oct144654712113
937835884858
1013534205003
1158157845a0
1227586b268b
131378c71a37
149256a664b
155432c4c38
hex326b3944b

13534205003 has 4 divisors (see below), whose sum is σ = 14764587288. Its totient is φ = 12303822720.

The previous prime is 13534204973. The next prime is 13534205021. The reversal of 13534205003 is 30050243531.

13534205003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13534205003 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13534205803) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 615191126 + ... + 615191147.

It is an arithmetic number, because the mean of its divisors is an integer number (3691146822).

Almost surely, 213534205003 is an apocalyptic number.

13534205003 is a deficient number, since it is larger than the sum of its proper divisors (1230382285).

13534205003 is a wasteful number, since it uses less digits than its factorization.

13534205003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1230382284.

The product of its (nonzero) digits is 5400, while the sum is 26.

Adding to 13534205003 its reverse (30050243531), we get a palindrome (43584448534).

The spelling of 13534205003 in words is "thirteen billion, five hundred thirty-four million, two hundred five thousand, three".

Divisors: 1 11 1230382273 13534205003