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1353542304019 is a prime number
BaseRepresentation
bin10011101100100101011…
…010001000000100010011
311210101201200122022110011
4103230211122020010103
5134134023312212034
62513450405015351
7166535016516163
oct23544532100423
94711650568404
101353542304019
11482041386724
1219a3aa6b4557
139a83b9c5c39
144972452a5a3
152531e781864
hex13b25688113

1353542304019 has 2 divisors, whose sum is σ = 1353542304020. Its totient is φ = 1353542304018.

The previous prime is 1353542303999. The next prime is 1353542304031. The reversal of 1353542304019 is 9104032453531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1353542304019 - 227 = 1353408086291 is a prime.

It is a super-2 number, since 2×13535423040192 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1353542004019) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676771152009 + 676771152010.

It is an arithmetic number, because the mean of its divisors is an integer number (676771152010).

Almost surely, 21353542304019 is an apocalyptic number.

1353542304019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353542304019 is an equidigital number, since it uses as much as digits as its factorization.

1353542304019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 40.

It can be divided in two parts, 1353542 and 304019, that added together give a palindrome (1657561).

The spelling of 1353542304019 in words is "one trillion, three hundred fifty-three billion, five hundred forty-two million, three hundred four thousand, nineteen".