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1353542304031 is a prime number
BaseRepresentation
bin10011101100100101011…
…010001000000100011111
311210101201200122022110121
4103230211122020010133
5134134023312212111
62513450405015411
7166535016516211
oct23544532100437
94711650568417
101353542304031
11482041386735
1219a3aa6b4567
139a83b9c5c48
144972452a5b1
152531e781871
hex13b2568811f

1353542304031 has 2 divisors, whose sum is σ = 1353542304032. Its totient is φ = 1353542304030.

The previous prime is 1353542304019. The next prime is 1353542304041. The reversal of 1353542304031 is 1304032453531.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1353542304031 - 25 = 1353542303999 is a prime.

It is a super-2 number, since 2×13535423040312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1353542304041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676771152015 + 676771152016.

It is an arithmetic number, because the mean of its divisors is an integer number (676771152016).

Almost surely, 21353542304031 is an apocalyptic number.

1353542304031 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353542304031 is an equidigital number, since it uses as much as digits as its factorization.

1353542304031 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 64800, while the sum is 34.

Adding to 1353542304031 its reverse (1304032453531), we get a palindrome (2657574757562).

The spelling of 1353542304031 in words is "one trillion, three hundred fifty-three billion, five hundred forty-two million, three hundred four thousand, thirty-one".