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1353542304032 = 2545199360079
BaseRepresentation
bin10011101100100101011…
…010001000000100100000
311210101201200122022110122
4103230211122020010200
5134134023312212112
62513450405015412
7166535016516212
oct23544532100440
94711650568418
101353542304032
11482041386736
1219a3aa6b4568
139a83b9c5c49
144972452a5b2
152531e781872
hex13b25688120

1353542304032 has 24 divisors (see below), whose sum is σ = 2665376380800. Its totient is φ = 676621318464.

The previous prime is 1353542304031. The next prime is 1353542304041. The reversal of 1353542304032 is 2304032453531.

It is a junction number, because it is equal to n+sod(n) for n = 1353542303983 and 1353542304001.

It is not an unprimeable number, because it can be changed into a prime (1353542304031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4535432 + ... + 4824647.

It is an arithmetic number, because the mean of its divisors is an integer number (111057349200).

Almost surely, 21353542304032 is an apocalyptic number.

It is an amenable number.

1353542304032 is a deficient number, since it is larger than the sum of its proper divisors (1311834076768).

1353542304032 is an equidigital number, since it uses as much as digits as its factorization.

1353542304032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9364608 (or 9364600 counting only the distinct ones).

The product of its (nonzero) digits is 129600, while the sum is 35.

Adding to 1353542304032 its reverse (2304032453531), we get a palindrome (3657574757563).

The spelling of 1353542304032 in words is "one trillion, three hundred fifty-three billion, five hundred forty-two million, three hundred four thousand, thirty-two".

Divisors: 1 2 4 8 16 32 4519 9038 18076 36152 72304 144608 9360079 18720158 37440316 74880632 149761264 299522528 42298197001 84596394002 169192788004 338385576008 676771152016 1353542304032