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13535552057 is a prime number
BaseRepresentation
bin11001001101100100…
…00010001000111001
31021221022112021202212
430212302002020321
5210210100131212
610115041504505
7656265202616
oct144662021071
937838467685
1013535552057
115816514665
122759042135
131379323c01
1492593750d
1554348de22
hex326c82239

13535552057 has 2 divisors, whose sum is σ = 13535552058. Its totient is φ = 13535552056.

The previous prime is 13535552027. The next prime is 13535552059. The reversal of 13535552057 is 75025553531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10627754281 + 2907797776 = 103091^2 + 53924^2 .

It is a cyclic number.

It is not a de Polignac number, because 13535552057 - 26 = 13535551993 is a prime.

It is a super-2 number, since 2×135355520572 (a number of 21 digits) contains 22 as substring.

Together with 13535552059, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13535552059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767776028 + 6767776029.

It is an arithmetic number, because the mean of its divisors is an integer number (6767776029).

Almost surely, 213535552057 is an apocalyptic number.

It is an amenable number.

13535552057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13535552057 is an equidigital number, since it uses as much as digits as its factorization.

13535552057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 393750, while the sum is 41.

The spelling of 13535552057 in words is "thirteen billion, five hundred thirty-five million, five hundred fifty-two thousand, fifty-seven".