Base | Representation |
---|---|
bin | 10011101100101010001… |
… | …010101100000101101111 |
3 | 11210101221020212120102011 |
4 | 103230222022230011233 |
5 | 134134204232041333 |
6 | 2513502340142051 |
7 | 166540006242661 |
oct | 23545212540557 |
9 | 4711836776364 |
10 | 1353622143343 |
11 | 482082458138 |
12 | 19a411397927 |
13 | 9a8523cb142 |
14 | 49730d90531 |
15 | 253267a29cd |
hex | 13b2a2ac16f |
1353622143343 has 2 divisors, whose sum is σ = 1353622143344. Its totient is φ = 1353622143342.
The previous prime is 1353622143323. The next prime is 1353622143403. The reversal of 1353622143343 is 3433412263531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1353622143343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1353622143296 and 1353622143305.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1353622143323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676811071671 + 676811071672.
It is an arithmetic number, because the mean of its divisors is an integer number (676811071672).
Almost surely, 21353622143343 is an apocalyptic number.
1353622143343 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353622143343 is an equidigital number, since it uses as much as digits as its factorization.
1353622143343 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 466560, while the sum is 40.
The spelling of 1353622143343 in words is "one trillion, three hundred fifty-three billion, six hundred twenty-two million, one hundred forty-three thousand, three hundred forty-three".
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