Base | Representation |
---|---|
bin | 10011101100101010001… |
… | …010101100000110101011 |
3 | 11210101221020212120111101 |
4 | 103230222022230012223 |
5 | 134134204232042103 |
6 | 2513502340142231 |
7 | 166540006243105 |
oct | 23545212540653 |
9 | 4711836776441 |
10 | 1353622143403 |
11 | 482082458192 |
12 | 19a411397977 |
13 | 9a8523cb18a |
14 | 49730d90575 |
15 | 253267a2a1d |
hex | 13b2a2ac1ab |
1353622143403 has 2 divisors, whose sum is σ = 1353622143404. Its totient is φ = 1353622143402.
The previous prime is 1353622143343. The next prime is 1353622143449. The reversal of 1353622143403 is 3043412263531.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (3043412263531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1353622143403 - 29 = 1353622142891 is a prime.
It is a super-2 number, since 2×13536221434032 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1353622143103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676811071701 + 676811071702.
It is an arithmetic number, because the mean of its divisors is an integer number (676811071702).
Almost surely, 21353622143403 is an apocalyptic number.
1353622143403 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353622143403 is an equidigital number, since it uses as much as digits as its factorization.
1353622143403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 37.
The spelling of 1353622143403 in words is "one trillion, three hundred fifty-three billion, six hundred twenty-two million, one hundred forty-three thousand, four hundred three".
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