Base | Representation |
---|---|
bin | 10011101100101010001… |
… | …010101100000101111001 |
3 | 11210101221020212120102112 |
4 | 103230222022230011321 |
5 | 134134204232041403 |
6 | 2513502340142105 |
7 | 166540006243004 |
oct | 23545212540571 |
9 | 4711836776375 |
10 | 1353622143353 |
11 | 482082458147 |
12 | 19a411397935 |
13 | 9a8523cb14c |
14 | 49730d9053b |
15 | 253267a29d8 |
hex | 13b2a2ac179 |
1353622143353 has 4 divisors (see below), whose sum is σ = 1353626711808. Its totient is φ = 1353617574900.
The previous prime is 1353622143343. The next prime is 1353622143403. The reversal of 1353622143353 is 3533412263531.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1353622143353 - 224 = 1353605366137 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1353622143353.
It is not an unprimeable number, because it can be changed into a prime (1353622143323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1806473 + ... + 2443478.
It is an arithmetic number, because the mean of its divisors is an integer number (338406677952).
Almost surely, 21353622143353 is an apocalyptic number.
It is an amenable number.
1353622143353 is a deficient number, since it is larger than the sum of its proper divisors (4568455).
1353622143353 is an equidigital number, since it uses as much as digits as its factorization.
1353622143353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4568454.
The product of its digits is 583200, while the sum is 41.
The spelling of 1353622143353 in words is "one trillion, three hundred fifty-three billion, six hundred twenty-two million, one hundred forty-three thousand, three hundred fifty-three".
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