Base | Representation |
---|---|
bin | 1100010011111011011101… |
… | …1110011010001111110111 |
3 | 1202221002010100211012001021 |
4 | 3010332313132122033313 |
5 | 3233240243124331210 |
6 | 44442331433242011 |
7 | 2564660405553415 |
oct | 304766736321767 |
9 | 52832110735037 |
10 | 13536520152055 |
11 | 4349895802a3a |
12 | 1627575263307 |
13 | 772646c56804 |
14 | 34b2575c22b5 |
15 | 1871b1525bda |
hex | c4fb779a3f7 |
13536520152055 has 64 divisors (see below), whose sum is σ = 16866183979008. Its totient is φ = 10423719290880.
The previous prime is 13536520151993. The next prime is 13536520152073. The reversal of 13536520152055 is 55025102563531.
It is not a de Polignac number, because 13536520152055 - 29 = 13536520151543 is a prime.
It is a super-2 number, since 2×135365201520552 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2340740694 + ... + 2340746476.
It is an arithmetic number, because the mean of its divisors is an integer number (263534124672).
Almost surely, 213536520152055 is an apocalyptic number.
13536520152055 is a deficient number, since it is larger than the sum of its proper divisors (3329663826953).
13536520152055 is a wasteful number, since it uses less digits than its factorization.
13536520152055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6616.
The product of its (nonzero) digits is 675000, while the sum is 43.
The spelling of 13536520152055 in words is "thirteen trillion, five hundred thirty-six billion, five hundred twenty million, one hundred fifty-two thousand, fifty-five".
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