13540150391 has 2 divisors, whose sum is σ = 13540150392. Its totient is φ = 13540150390.

The previous prime is 13540150343. The next prime is 13540150423. The reversal of 13540150391 is 19305104531.

It is an a-pointer prime, because the next prime (13540150423) can be obtained adding 13540150391 to its sum of digits (32).

It is a strong prime.

It is an emirp because it is prime and its reverse (19305104531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13540150391 - 2¹⁰ = 13540149367 is a prime.

It is a super-5 number, since 5×13540150391⁵ (a number of 52 digits) contains 55555 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13540153391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770075195 + 6770075196.

It is an arithmetic number, because the mean of its divisors is an integer number (6770075196).

Almost surely, 2^13540150391 is an apocalyptic number.

13540150391 is a deficient number, since it is larger than the sum of its proper divisors (1).

13540150391 is an equidigital number, since it uses as much as digits as its factorization.

13540150391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 32.

The spelling of 13540150391 in words is "thirteen billion, five hundred forty million, one hundred fifty thousand, three hundred ninety-one".