13540254033 has 4 divisors (see below), whose sum is σ = 18053672048. Its totient is φ = 9026836020.

The previous prime is 13540254011. The next prime is 13540254043. The reversal of 13540254033 is 33045204531.

13540254033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13540254033 - 2⁸ = 13540253777 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13540254043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2256709003 + ... + 2256709008.

It is an arithmetic number, because the mean of its divisors is an integer number (4513418012).

Almost surely, 2^13540254033 is an apocalyptic number.

It is an amenable number.

13540254033 is a deficient number, since it is larger than the sum of its proper divisors (4513418015).

13540254033 is an equidigital number, since it uses as much as digits as its factorization.

13540254033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4513418014.

The product of its (nonzero) digits is 21600, while the sum is 30.

Adding to 13540254033 its reverse (33045204531), we get a palindrome (46585458564).

The spelling of 13540254033 in words is "thirteen billion, five hundred forty million, two hundred fifty-four thousand, thirty-three".