1354041161 has 4 divisors (see below), whose sum is σ = 1477135824. Its totient is φ = 1230946500.

The previous prime is 1354041133. The next prime is 1354041203. The reversal of 1354041161 is 1611404531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 1611404531 = 11 ⋅146491321.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1354041161 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1354041161.

It is not an unprimeable number, because it can be changed into a prime (1354041961) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61547315 + ... + 61547336.

It is an arithmetic number, because the mean of its divisors is an integer number (369283956).

Almost surely, 2^1354041161 is an apocalyptic number.

1354041161 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1354041161 is a deficient number, since it is larger than the sum of its proper divisors (123094663).

1354041161 is a wasteful number, since it uses less digits than its factorization.

1354041161 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123094662.

The product of its (nonzero) digits is 1440, while the sum is 26.

The square root of 1354041161 is about 36797.2982839773. The cubic root of 1354041161 is about 1106.3111483920.

Adding to 1354041161 its reverse (1611404531), we get a palindrome (2965445692).

The spelling of 1354041161 in words is "one billion, three hundred fifty-four million, forty-one thousand, one hundred sixty-one".