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1354101303431 is a prime number
BaseRepresentation
bin10011101101000110101…
…110100010100010000111
311210110011122111102111002
4103231012232202202013
5134141144413202211
62514022054203515
7166554615112112
oct23550656424207
94713148442432
101354101303431
114822a8980208
1219a52595359b
139a8ca767716
144977887d579
15253538a103b
hex13b46ba2887

1354101303431 has 2 divisors, whose sum is σ = 1354101303432. Its totient is φ = 1354101303430.

The previous prime is 1354101303427. The next prime is 1354101303449. The reversal of 1354101303431 is 1343031014531.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1354101303431 - 22 = 1354101303427 is a prime.

It is a super-2 number, since 2×13541013034312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1354101303394 and 1354101303403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354101303481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677050651715 + 677050651716.

It is an arithmetic number, because the mean of its divisors is an integer number (677050651716).

Almost surely, 21354101303431 is an apocalyptic number.

1354101303431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354101303431 is an equidigital number, since it uses as much as digits as its factorization.

1354101303431 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6480, while the sum is 29.

Adding to 1354101303431 its reverse (1343031014531), we get a palindrome (2697132317962).

The spelling of 1354101303431 in words is "one trillion, three hundred fifty-four billion, one hundred one million, three hundred three thousand, four hundred thirty-one".