Base | Representation |
---|---|
bin | 111111000011100010… |
… | …1011101000111110111 |
3 | 110221111222110000022111 |
4 | 1332013011131013313 |
5 | 4204310021342333 |
6 | 142112345311451 |
7 | 12532410621235 |
oct | 1760705350767 |
9 | 427458400274 |
10 | 135410340343 |
11 | 52477674993 |
12 | 222b0795587 |
13 | c9cca55455 |
14 | 67a7c63955 |
15 | 37c7d224cd |
hex | 1f8715d1f7 |
135410340343 has 4 divisors (see below), whose sum is σ = 135412125840. Its totient is φ = 135408554848.
The previous prime is 135410340281. The next prime is 135410340367. The reversal of 135410340343 is 343043014531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135410340343 - 213 = 135410332151 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135410341343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 773698 + ... + 932431.
It is an arithmetic number, because the mean of its divisors is an integer number (33853031460).
Almost surely, 2135410340343 is an apocalyptic number.
135410340343 is a deficient number, since it is larger than the sum of its proper divisors (1785497).
135410340343 is an equidigital number, since it uses as much as digits as its factorization.
135410340343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1785496.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 135410340343 its reverse (343043014531), we get a palindrome (478453354874).
The spelling of 135410340343 in words is "one hundred thirty-five billion, four hundred ten million, three hundred forty thousand, three hundred forty-three".
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