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135415134400000 = 29557131396691
BaseRepresentation
bin11110110010100011001010…
…111110111010111000000000
3122202110120010112201222000011
4132302203022332322320000
5120222120143401300000
61200000504241234304
740344264160512040
oct3662431276727000
9582416115658004
10135415134400000
113a169266115884
121323043a632994
135a737915ccc50
1425621adb15720
15109c6d21c52ba
hex7b28cafbae00

135415134400000 has 960 divisors, whose sum is σ = 419285519009280. Its totient is φ = 42541977600000.

The previous prime is 135415134399947. The next prime is 135415134400001. The reversal of 135415134400000 is 4431514531.

135415134400000 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135415134400001) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 20238396655 + ... + 20238403345.

It is an arithmetic number, because the mean of its divisors is an integer number (436755748968).

Almost surely, 2135415134400000 is an apocalyptic number.

135415134400000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 135415134400000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (209642759504640).

135415134400000 is an abundant number, since it is smaller than the sum of its proper divisors (283870384609280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

135415134400000 is an frugal number, since it uses more digits than its factorization.

135415134400000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6893 (or 6857 counting only the distinct ones).

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 135415134400000 its reverse (4431514531), we get a palindrome (135419565914531).

The spelling of 135415134400000 in words is "one hundred thirty-five trillion, four hundred fifteen billion, one hundred thirty-four million, four hundred thousand".