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13541555345 = 52708311069
BaseRepresentation
bin11001001110010001…
…11011110010010001
31021221201211021201212
430213020323302101
5210213114232340
610115414305505
7656400215123
oct144710736221
937851737655
1013541555345
115819944a5a
12275b058295
13137a646556
1492665b213
15543c77a65
hex32723bc91

13541555345 has 4 divisors (see below), whose sum is σ = 16249866420. Its totient is φ = 10833244272.

The previous prime is 13541555299. The next prime is 13541555351. The reversal of 13541555345 is 54355514531.

13541555345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 2251217809 + 11290337536 = 47447^2 + 106256^2 .

It is a cyclic number.

It is not a de Polignac number, because 13541555345 - 212 = 13541551249 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1354155530 + ... + 1354155539.

It is an arithmetic number, because the mean of its divisors is an integer number (4062466605).

Almost surely, 213541555345 is an apocalyptic number.

It is an amenable number.

13541555345 is a deficient number, since it is larger than the sum of its proper divisors (2708311075).

13541555345 is an equidigital number, since it uses as much as digits as its factorization.

13541555345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2708311074.

The product of its digits is 450000, while the sum is 41.

The spelling of 13541555345 in words is "thirteen billion, five hundred forty-one million, five hundred fifty-five thousand, three hundred forty-five".

Divisors: 1 5 2708311069 13541555345