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135431400215 = 591272967709
BaseRepresentation
bin111111000100001010…
…1110010101100010111
3110221120110001222000202
41332020111302230113
54204330414301330
6142114420531115
712533054623256
oct1761025625427
9427513058022
10135431400215
1152488549541
12222b7850a9b
13ca0421a107
1467aa98679d
1537c9ad2445
hex1f88572b17

135431400215 has 8 divisors (see below), whose sum is σ = 162535541280. Its totient is φ = 108333212832.

The previous prime is 135431400197. The next prime is 135431400239. The reversal of 135431400215 is 512004134531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 135431400215 - 212 = 135431396119 is a prime.

It is a super-3 number, since 3×1354314002153 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1438220 + ... + 1529489.

It is an arithmetic number, because the mean of its divisors is an integer number (20316942660).

Almost surely, 2135431400215 is an apocalyptic number.

135431400215 is a deficient number, since it is larger than the sum of its proper divisors (27104141065).

135431400215 is an equidigital number, since it uses as much as digits as its factorization.

135431400215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2976841.

The product of its (nonzero) digits is 7200, while the sum is 29.

Adding to 135431400215 its reverse (512004134531), we get a palindrome (647435534746).

The spelling of 135431400215 in words is "one hundred thirty-five billion, four hundred thirty-one million, four hundred thousand, two hundred fifteen".

Divisors: 1 5 9127 45635 2967709 14838545 27086280043 135431400215