Base | Representation |
---|---|
bin | 10011101101010100100… |
… | …010100000111100110101 |
3 | 11210110202210112110122202 |
4 | 103231110202200330311 |
5 | 134142133224012440 |
6 | 2514101053034245 |
7 | 166563430555244 |
oct | 23552442407465 |
9 | 4713683473582 |
10 | 1354333032245 |
11 | 482407764526 |
12 | 19a58b485985 |
13 | 9a93678086b |
14 | 4979b56095b |
15 | 25368dc6615 |
hex | 13b548a0f35 |
1354333032245 has 8 divisors (see below), whose sum is σ = 1625698338720. Its totient is φ = 1083133959120.
The previous prime is 1354333032223. The next prime is 1354333032259. The reversal of 1354333032245 is 5422303334531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1354333032245 - 224 = 1354316255029 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1354333032199 and 1354333032208.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41540411 + ... + 41573000.
It is an arithmetic number, because the mean of its divisors is an integer number (203212292340).
Almost surely, 21354333032245 is an apocalyptic number.
It is an amenable number.
1354333032245 is a deficient number, since it is larger than the sum of its proper divisors (271365306475).
1354333032245 is an equidigital number, since it uses as much as digits as its factorization.
1354333032245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 83116675.
The product of its (nonzero) digits is 388800, while the sum is 38.
Adding to 1354333032245 its reverse (5422303334531), we get a palindrome (6776636366776).
The spelling of 1354333032245 in words is "one trillion, three hundred fifty-four billion, three hundred thirty-three million, thirty-two thousand, two hundred forty-five".
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