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13543412020 = 225969769833
BaseRepresentation
bin11001001110100000…
…00001000100110100
31021221212022121121121
430213100001010310
5210214103141040
610115522153324
7656422050145
oct144720010464
937855277547
1013543412020
11581a9a29a6
12275b7b2844
13137ab46688
149269c1acc
15543ee2c4a
hex327401134

13543412020 has 24 divisors (see below), whose sum is σ = 28444505544. Its totient is φ = 5416728576.

The previous prime is 13543411993. The next prime is 13543412101. The reversal of 13543412020 is 2021434531.

It can be written as a sum of positive squares in 4 ways, for example, as 354267684 + 13189144336 = 18822^2 + 114844^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 159024 + ... + 228856.

It is an arithmetic number, because the mean of its divisors is an integer number (1185187731).

Almost surely, 213543412020 is an apocalyptic number.

13543412020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13543412020 is an abundant number, since it is smaller than the sum of its proper divisors (14901093524).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13543412020 is a wasteful number, since it uses less digits than its factorization.

13543412020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79539 (or 79537 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 13543412020 its reverse (2021434531), we get a palindrome (15564846551).

The spelling of 13543412020 in words is "thirteen billion, five hundred forty-three million, four hundred twelve thousand, twenty".

Divisors: 1 2 4 5 10 20 9697 19394 38788 48485 69833 96970 139666 193940 279332 349165 698330 1396660 677170601 1354341202 2708682404 3385853005 6771706010 13543412020