Base | Representation |
---|---|
bin | 11110110010111100101101… |
… | …011001110110110001110111 |
3 | 122202120011220120020201102222 |
4 | 132302330231121312301313 |
5 | 120223042323142311210 |
6 | 1200021241225152555 |
7 | 40346254533444644 |
oct | 3662745531666167 |
9 | 582504816221388 |
10 | 135442555432055 |
11 | 3a17995761a043 |
12 | 1323581192b75b |
13 | 5a762415a71c1 |
14 | 2563651834dcb |
15 | 109d2896c5655 |
hex | 7b2f2d676c77 |
135442555432055 has 8 divisors (see below), whose sum is σ = 162560927118192. Its totient is φ = 108334137279168.
The previous prime is 135442555432031. The next prime is 135442555432109. The reversal of 135442555432055 is 550234555244531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 135442555432055 - 222 = 135442551237751 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135442555431988 and 135442555432006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2488353374 + ... + 2488407803.
It is an arithmetic number, because the mean of its divisors is an integer number (20320115889774).
Almost surely, 2135442555432055 is an apocalyptic number.
135442555432055 is a deficient number, since it is larger than the sum of its proper divisors (27118371686137).
135442555432055 is an equidigital number, since it uses as much as digits as its factorization.
135442555432055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4976766625.
The product of its (nonzero) digits is 36000000, while the sum is 53.
The spelling of 135442555432055 in words is "one hundred thirty-five trillion, four hundred forty-two billion, five hundred fifty-five million, four hundred thirty-two thousand, fifty-five".
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