Base | Representation |
---|---|
bin | 11110110011001110011010… |
… | …100001111010100011101100 |
3 | 122202121222222110020020222010 |
4 | 132303032122201322203230 |
5 | 120223400241412133122 |
6 | 1200034103454321220 |
7 | 40350526613636334 |
oct | 3663163241724354 |
9 | 582558873206863 |
10 | 135461566130412 |
11 | 3a186a226720a5 |
12 | 132394384b9210 |
13 | 5a77c8101c342 |
14 | 25645365960c4 |
15 | 109d9ed674e0c |
hex | 7b339a87a8ec |
135461566130412 has 48 divisors (see below), whose sum is σ = 334697677050240. Its totient is φ = 42494200150272.
The previous prime is 135461566130333. The next prime is 135461566130417. The reversal of 135461566130412 is 214031665164531.
It is not an unprimeable number, because it can be changed into a prime (135461566130417) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 25252462 + ... + 30143157.
It is an arithmetic number, because the mean of its divisors is an integer number (6972868271880).
Almost surely, 2135461566130412 is an apocalyptic number.
135461566130412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
135461566130412 is an abundant number, since it is smaller than the sum of its proper divisors (199236110919828).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135461566130412 is a wasteful number, since it uses less digits than its factorization.
135461566130412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 55407630 (or 55407628 counting only the distinct ones).
The product of its (nonzero) digits is 1555200, while the sum is 48.
The spelling of 135461566130412 in words is "one hundred thirty-five trillion, four hundred sixty-one billion, five hundred sixty-six million, one hundred thirty thousand, four hundred twelve".
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