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1354928117 is a prime number
BaseRepresentation
bin101000011000010…
…1000111111110101
310111102112110221212
41100300220333311
510233330144432
6342240451205
745401461514
oct12060507765
93442473855
101354928117
11635904604
12319919b05
1318792a51a
14cbd3c67b
157de402b2
hex50c28ff5

1354928117 has 2 divisors, whose sum is σ = 1354928118. Its totient is φ = 1354928116.

The previous prime is 1354928089. The next prime is 1354928119. The reversal of 1354928117 is 7118294531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1351371121 + 3556996 = 36761^2 + 1886^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1354928117 is a prime.

Together with 1354928119, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1354928119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677464058 + 677464059.

It is an arithmetic number, because the mean of its divisors is an integer number (677464059).

Almost surely, 21354928117 is an apocalyptic number.

It is an amenable number.

1354928117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1354928117 is an equidigital number, since it uses as much as digits as its factorization.

1354928117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 60480, while the sum is 41.

The square root of 1354928117 is about 36809.3482284052. The cubic root of 1354928117 is about 1106.5526563470.

The spelling of 1354928117 in words is "one billion, three hundred fifty-four million, nine hundred twenty-eight thousand, one hundred seventeen".