Base | Representation |
---|---|
bin | 11001001111010010… |
… | …01110101101001111 |
3 | 1021222022202102001111 |
4 | 30213221032231033 |
5 | 210222301141310 |
6 | 10120315552451 |
7 | 656532165505 |
oct | 144751165517 |
9 | 37868672044 |
10 | 13550021455 |
11 | 58236a7743 |
12 | 2761a5b727 |
13 | 137c31bb99 |
14 | 927822675 |
15 | 54489b28a |
hex | 327a4eb4f |
13550021455 has 8 divisors (see below), whose sum is σ = 16293974400. Its totient is φ = 10817384736.
The previous prime is 13550021447. The next prime is 13550021467. The reversal of 13550021455 is 55412005531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13550021455 - 23 = 13550021447 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2826420 + ... + 2831209.
It is an arithmetic number, because the mean of its divisors is an integer number (2036746800).
Almost surely, 213550021455 is an apocalyptic number.
13550021455 is a deficient number, since it is larger than the sum of its proper divisors (2743952945).
13550021455 is an equidigital number, since it uses as much as digits as its factorization.
13550021455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5658113.
The product of its (nonzero) digits is 15000, while the sum is 31.
Adding to 13550021455 its reverse (55412005531), we get a palindrome (68962026986).
The spelling of 13550021455 in words is "thirteen billion, five hundred fifty million, twenty-one thousand, four hundred fifty-five".
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