13550506216151 has 2 divisors, whose sum is σ = 13550506216152. Its totient is φ = 13550506216150.

The previous prime is 13550506216103. The next prime is 13550506216153. The reversal of 13550506216151 is 15161260505531.

13550506216151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13550506216151 is a prime.

Together with 13550506216153, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13550506216099 and 13550506216108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13550506216153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6775253108075 + 6775253108076.

It is an arithmetic number, because the mean of its divisors is an integer number (6775253108076).

Almost surely, 2^{13550506216151} is an apocalyptic number.

13550506216151 is a deficient number, since it is larger than the sum of its proper divisors (1).

13550506216151 is an equidigital number, since it uses as much as digits as its factorization.

13550506216151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135000, while the sum is 41.

The spelling of 13550506216151 in words is "thirteen trillion, five hundred fifty billion, five hundred six million, two hundred sixteen thousand, one hundred fifty-one".