Base | Representation |
---|---|
bin | 11110110011110111010111… |
… | …101001010100011000011111 |
3 | 122202210012111010222221011212 |
4 | 132303313113221110120133 |
5 | 120230110322013414320 |
6 | 1200110215231535035 |
7 | 40353644426321222 |
oct | 3663672751243037 |
9 | 582705433887155 |
10 | 135505541154335 |
11 | 3a1a36393a5480 |
12 | 13245a6b68a47b |
13 | 5a7c16b789c61 |
14 | 2566708a555b9 |
15 | 109ec240eb9c5 |
hex | 7b3dd7a5461f |
135505541154335 has 32 divisors (see below), whose sum is σ = 181250287137792. Its totient is φ = 96406378404480.
The previous prime is 135505541154331. The next prime is 135505541154377. The reversal of 135505541154335 is 533451145505531.
It is not a de Polignac number, because 135505541154335 - 22 = 135505541154331 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135505541154331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7198244 + ... + 17967353.
It is an arithmetic number, because the mean of its divisors is an integer number (5664071473056).
Almost surely, 2135505541154335 is an apocalyptic number.
135505541154335 is a deficient number, since it is larger than the sum of its proper divisors (45744745983457).
135505541154335 is a wasteful number, since it uses less digits than its factorization.
135505541154335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25167743.
The product of its (nonzero) digits is 6750000, while the sum is 50.
Adding to 135505541154335 its reverse (533451145505531), we get a palindrome (668956686659866).
The spelling of 135505541154335 in words is "one hundred thirty-five trillion, five hundred five billion, five hundred forty-one million, one hundred fifty-four thousand, three hundred thirty-five".
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