Base | Representation |
---|---|
bin | 10011101110000011101… |
… | …011111110001010110111 |
3 | 11210112210220221211211011 |
4 | 103232003223332022313 |
5 | 134200243223243000 |
6 | 2514311351053051 |
7 | 166622144201350 |
oct | 23560353761267 |
9 | 4715726854734 |
10 | 1355124040375 |
11 | 482783213656 |
12 | 19a770371187 |
13 | 9aa31605a01 |
14 | 49834628d27 |
15 | 253b35742ba |
hex | 13b83afe2b7 |
1355124040375 has 16 divisors (see below), whose sum is σ = 1932794061120. Its totient is φ = 929227912800.
The previous prime is 1355124040373. The next prime is 1355124040427. The reversal of 1355124040375 is 5730404215531.
It is not a de Polignac number, because 1355124040375 - 21 = 1355124040373 is a prime.
It is a super-2 number, since 2×13551240403752 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1355124040373) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 774355720 + ... + 774357469.
It is an arithmetic number, because the mean of its divisors is an integer number (120799628820).
Almost surely, 21355124040375 is an apocalyptic number.
1355124040375 is a deficient number, since it is larger than the sum of its proper divisors (577670020745).
1355124040375 is an equidigital number, since it uses as much as digits as its factorization.
1355124040375 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1548713211 (or 1548713201 counting only the distinct ones).
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 1355124040375 in words is "one trillion, three hundred fifty-five billion, one hundred twenty-four million, forty thousand, three hundred seventy-five".
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