Base | Representation |
---|---|
bin | 10011101110001011010… |
… | …000110010111100100101 |
3 | 11210120010210002212211112 |
4 | 103232023100302330211 |
5 | 134201023242243440 |
6 | 2514332131114405 |
7 | 166625246366411 |
oct | 23561320627445 |
9 | 4716123085745 |
10 | 1355251134245 |
11 | 482838a30108 |
12 | 19a7a6a42a05 |
13 | 9aa51a44798 |
14 | 4984746dd41 |
15 | 253be7cb965 |
hex | 13b8b432f25 |
1355251134245 has 8 divisors (see below), whose sum is σ = 1626318274560. Its totient is φ = 1084189631760.
The previous prime is 1355251134241. The next prime is 1355251134283. The reversal of 1355251134245 is 5424311525531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1355251134245 - 22 = 1355251134241 is a prime.
It is a super-3 number, since 3×13552511342453 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1355251134241) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 861221 + ... + 1858010.
It is an arithmetic number, because the mean of its divisors is an integer number (203289784320).
Almost surely, 21355251134245 is an apocalyptic number.
It is an amenable number.
1355251134245 is a deficient number, since it is larger than the sum of its proper divisors (271067140315).
1355251134245 is an equidigital number, since it uses as much as digits as its factorization.
1355251134245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2818915.
The product of its digits is 360000, while the sum is 41.
Adding to 1355251134245 its reverse (5424311525531), we get a palindrome (6779562659776).
The spelling of 1355251134245 in words is "one trillion, three hundred fifty-five billion, two hundred fifty-one million, one hundred thirty-four thousand, two hundred forty-five".
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