Base | Representation |
---|---|
bin | 111111000111000111… |
… | …1101011001110010111 |
3 | 110221211100110201120201 |
4 | 1332032033223032113 |
5 | 4210031244210210 |
6 | 142132320041331 |
7 | 12535366621414 |
oct | 1761617531627 |
9 | 427740421521 |
10 | 135530460055 |
11 | 52529458681 |
12 | 22324a63247 |
13 | ca1b8c19c3 |
14 | 67b9bb110b |
15 | 37d364d53a |
hex | 1f8e3eb397 |
135530460055 has 4 divisors (see below), whose sum is σ = 162636552072. Its totient is φ = 108424368040.
The previous prime is 135530460041. The next prime is 135530460061. The reversal of 135530460055 is 550064035531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 550064035531 = 157 ⋅3503592583.
It is not a de Polignac number, because 135530460055 - 27 = 135530459927 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 135530459996 and 135530460023.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13553046001 + ... + 13553046010.
It is an arithmetic number, because the mean of its divisors is an integer number (40659138018).
Almost surely, 2135530460055 is an apocalyptic number.
135530460055 is a deficient number, since it is larger than the sum of its proper divisors (27106092017).
135530460055 is an equidigital number, since it uses as much as digits as its factorization.
135530460055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27106092016.
The product of its (nonzero) digits is 135000, while the sum is 37.
Adding to 135530460055 its reverse (550064035531), we get a palindrome (685594495586).
The spelling of 135530460055 in words is "one hundred thirty-five billion, five hundred thirty million, four hundred sixty thousand, fifty-five".
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