Base | Representation |
---|---|
bin | 11001001111110100… |
… | …00011010101100010 |
3 | 1021222122001110021012 |
4 | 30213322003111202 |
5 | 210224413300310 |
6 | 10120554300522 |
7 | 656614523336 |
oct | 144772032542 |
9 | 37878043235 |
10 | 13554431330 |
11 | 5826139970 |
12 | 2763427742 |
13 | 138020418b |
14 | 92824d7c6 |
15 | 544e6cc05 |
hex | 327e83562 |
13554431330 has 32 divisors (see below), whose sum is σ = 28181623680. Its totient is φ = 4638949120.
The previous prime is 13554431327. The next prime is 13554431339. The reversal of 13554431330 is 3313445531.
13554431330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13554431339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3622310 + ... + 3626049.
It is an arithmetic number, because the mean of its divisors is an integer number (880675740).
Almost surely, 213554431330 is an apocalyptic number.
13554431330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13554431330 is an abundant number, since it is smaller than the sum of its proper divisors (14627192350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13554431330 is a wasteful number, since it uses less digits than its factorization.
13554431330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7248394.
The product of its (nonzero) digits is 32400, while the sum is 32.
Adding to 13554431330 its reverse (3313445531), we get a palindrome (16867876861).
The spelling of 13554431330 in words is "thirteen billion, five hundred fifty-four million, four hundred thirty-one thousand, three hundred thirty".
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