Base | Representation |
---|---|
bin | 10011101110010110101… |
… | …111100000011100011101 |
3 | 11210120122012111222102221 |
4 | 103232112233200130131 |
5 | 134201422043444201 |
6 | 2514403211145341 |
7 | 166633105433536 |
oct | 23562657403435 |
9 | 4716565458387 |
10 | 1355443734301 |
11 | 482927719408 |
12 | 19a83b445251 |
13 | 9aa8290a807 |
14 | 49864c8768d |
15 | 253d16734a1 |
hex | 13b96be071d |
1355443734301 has 2 divisors, whose sum is σ = 1355443734302. Its totient is φ = 1355443734300.
The previous prime is 1355443734199. The next prime is 1355443734329. The reversal of 1355443734301 is 1034373445531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1355443135225 + 599076 = 1164235^2 + 774^2 .
It is a cyclic number.
It is not a de Polignac number, because 1355443734301 - 215 = 1355443701533 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1355443734401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677721867150 + 677721867151.
It is an arithmetic number, because the mean of its divisors is an integer number (677721867151).
Almost surely, 21355443734301 is an apocalyptic number.
It is an amenable number.
1355443734301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1355443734301 is an equidigital number, since it uses as much as digits as its factorization.
1355443734301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 907200, while the sum is 43.
The spelling of 1355443734301 in words is "one trillion, three hundred fifty-five billion, four hundred forty-three million, seven hundred thirty-four thousand, three hundred one".
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