Base | Representation |
---|---|
bin | 1100010101001000001110… |
… | …1011110000111111010111 |
3 | 1210000001022102111111101122 |
4 | 3011102003223300333113 |
5 | 3234104443233334302 |
6 | 44500020245514155 |
7 | 2566320136163513 |
oct | 305220353607727 |
9 | 53001272444348 |
10 | 13557126074327 |
11 | 43575aa265370 |
12 | 162b56611295b |
13 | 77457c021824 |
14 | 34c250153143 |
15 | 1879ba57e3a2 |
hex | c5483af0fd7 |
13557126074327 has 4 divisors (see below), whose sum is σ = 14789592081096. Its totient is φ = 12324660067560.
The previous prime is 13557126074299. The next prime is 13557126074381. The reversal of 13557126074327 is 72347062175531.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13557126074327 - 212 = 13557126070231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13557126004327) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 616233003368 + ... + 616233003389.
It is an arithmetic number, because the mean of its divisors is an integer number (3697398020274).
Almost surely, 213557126074327 is an apocalyptic number.
13557126074327 is a deficient number, since it is larger than the sum of its proper divisors (1232466006769).
13557126074327 is a wasteful number, since it uses less digits than its factorization.
13557126074327 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1232466006768.
The product of its (nonzero) digits is 7408800, while the sum is 53.
The spelling of 13557126074327 in words is "thirteen trillion, five hundred fifty-seven billion, one hundred twenty-six million, seventy-four thousand, three hundred twenty-seven".
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