Base | Representation |
---|---|
bin | 111111010001101010… |
… | …0101101011110100101 |
3 | 110222201222220120111112 |
4 | 1332203110231132211 |
5 | 4211242312222131 |
6 | 142231351514405 |
7 | 12550222543226 |
oct | 1764324553645 |
9 | 428658816445 |
10 | 135884101541 |
11 | 526a003a771 |
12 | 22403388a05 |
13 | ca76c51516 |
14 | 6810b4924d |
15 | 380470602b |
hex | 1fa352d7a5 |
135884101541 has 2 divisors, whose sum is σ = 135884101542. Its totient is φ = 135884101540.
The previous prime is 135884101513. The next prime is 135884101543. The reversal of 135884101541 is 145101488531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131612956225 + 4271145316 = 362785^2 + 65354^2 .
It is a cyclic number.
It is not a de Polignac number, because 135884101541 - 222 = 135879907237 is a prime.
Together with 135884101543, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135884101543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67942050770 + 67942050771.
It is an arithmetic number, because the mean of its divisors is an integer number (67942050771).
Almost surely, 2135884101541 is an apocalyptic number.
It is an amenable number.
135884101541 is a deficient number, since it is larger than the sum of its proper divisors (1).
135884101541 is an equidigital number, since it uses as much as digits as its factorization.
135884101541 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76800, while the sum is 41.
The spelling of 135884101541 in words is "one hundred thirty-five billion, eight hundred eighty-four million, one hundred one thousand, five hundred forty-one".
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