Base | Representation |
---|---|
bin | 111111010100010111… |
… | …1111000001100111001 |
3 | 110222222100011020212012 |
4 | 1332220233320030321 |
5 | 4211434112000213 |
6 | 142244402255305 |
7 | 12552406234322 |
oct | 1765057701471 |
9 | 428870136765 |
10 | 135975109433 |
11 | 5273744a2a9 |
12 | 22429957535 |
13 | ca8ca67147 |
14 | 681cc79449 |
15 | 380c6d14a8 |
hex | 1fa8bf8339 |
135975109433 has 24 divisors (see below), whose sum is σ = 157189886280. Its totient is φ = 117060088320.
The previous prime is 135975109429. The next prime is 135975109441. The reversal of 135975109433 is 334901579531.
It can be written as a sum of positive squares in 4 ways, for example, as 23732018704 + 112243090729 = 154052^2 + 335027^2 .
It is not a de Polignac number, because 135975109433 - 22 = 135975109429 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (135975109033) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 204038 + ... + 559983.
It is an arithmetic number, because the mean of its divisors is an integer number (6549578595).
Almost surely, 2135975109433 is an apocalyptic number.
It is an amenable number.
135975109433 is a deficient number, since it is larger than the sum of its proper divisors (21214776847).
135975109433 is a wasteful number, since it uses less digits than its factorization.
135975109433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 764105 (or 764086 counting only the distinct ones).
The product of its (nonzero) digits is 1530900, while the sum is 50.
The spelling of 135975109433 in words is "one hundred thirty-five billion, nine hundred seventy-five million, one hundred nine thousand, four hundred thirty-three".
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