Base | Representation |
---|---|
bin | 11001010101100111… |
… | …10101110010100111 |
3 | 1022010000200211122011 |
4 | 30222303311302213 |
5 | 210324400302011 |
6 | 10125454215051 |
7 | 661045510432 |
oct | 145263656247 |
9 | 38100624564 |
10 | 13603134631 |
11 | 5850684429 |
12 | 27777b4487 |
13 | 138a3272b8 |
14 | 9308ca819 |
15 | 54938d621 |
hex | 32acf5ca7 |
13603134631 has 8 divisors (see below), whose sum is σ = 13626877824. Its totient is φ = 13579409760.
The previous prime is 13603134617. The next prime is 13603134637. The reversal of 13603134631 is 13643130631.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13603134631 - 217 = 13603003559 is a prime.
It is a super-2 number, since 2×136031346312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13603134593 and 13603134602.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13603134637) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2813386 + ... + 2818216.
It is an arithmetic number, because the mean of its divisors is an integer number (1703359728).
Almost surely, 213603134631 is an apocalyptic number.
13603134631 is a deficient number, since it is larger than the sum of its proper divisors (23743193).
13603134631 is an equidigital number, since it uses as much as digits as its factorization.
13603134631 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9161.
The product of its (nonzero) digits is 11664, while the sum is 31.
The spelling of 13603134631 in words is "thirteen billion, six hundred three million, one hundred thirty-four thousand, six hundred thirty-one".
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