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136035112606433 is a prime number
BaseRepresentation
bin11110111011100100100100…
…100100000101101011100001
3122211122211101220010001120222
4132323210210210011223201
5120312244402311401213
61201153400142012425
740440132622354625
oct3673444444055341
9584584356101528
10136035112606433
113a388192702587
1213310623b77115
135aba096274481
1425841c540b185
1510ad8bae06808
hex7bb924905ae1

136035112606433 has 2 divisors, whose sum is σ = 136035112606434. Its totient is φ = 136035112606432.

The previous prime is 136035112606417. The next prime is 136035112606441. The reversal of 136035112606433 is 334606211530631.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 133297715884369 + 2737396722064 = 11545463^2 + 1654508^2 .

It is a cyclic number.

It is not a de Polignac number, because 136035112606433 - 24 = 136035112606417 is a prime.

It is not a weakly prime, because it can be changed into another prime (136035112606493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68017556303216 + 68017556303217.

It is an arithmetic number, because the mean of its divisors is an integer number (68017556303217).

Almost surely, 2136035112606433 is an apocalyptic number.

It is an amenable number.

136035112606433 is a deficient number, since it is larger than the sum of its proper divisors (1).

136035112606433 is an equidigital number, since it uses as much as digits as its factorization.

136035112606433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 699840, while the sum is 44.

The spelling of 136035112606433 in words is "one hundred thirty-six trillion, thirty-five billion, one hundred twelve million, six hundred six thousand, four hundred thirty-three".